The two consecutive, odd integers whose product equals 143 are 11 and 13.
There is no solution. 3*5*7 = 105 is too small, and the next three 5*7*9 = 315 is too large.
Their product is 143.
Assuming three consecutive years of no more than 52 consecutive beginnings of a week, 143 weeks is equal to 143/52 = 2.75 years.
Other than itself and 1, the only positive integer factors of 143 are 13 x 11.
11 and 13
You should be able to find this out quickly with trial and error. Or One more than the product will be the square of the even number between the two odds.
The two consecutive, odd integers whose product equals 143 are 11 and 13.
There is no solution. 3*5*7 = 105 is too small, and the next three 5*7*9 = 315 is too large.
Their product is 143.
11 and 12
17 and 19.
71+72=143
Assuming three consecutive years of no more than 52 consecutive beginnings of a week, 143 weeks is equal to 143/52 = 2.75 years.
Other than itself and 1, the only positive integer factors of 143 are 13 x 11.
This would be impossible. The closest result you can get is 45 + 47 + 49 = 141
11 x 13 = 143