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Q: Two consecutive odd integers such that their product is 143 more than 5 times their sum?

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They are -7 and -5.

One possible answer is -4 and -3.

The product is 30.

10-11-12

-1

The integers would begin with 10.

5872345098234783904672083946728390752430689723409687298290843 theres your answer

Consecutive integers are ...-3,-2,-1,0,1,2,3...One right after the other.Two consecutive integers would be 5 and then one more, 6.

Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.

Consecutive integers are integers that follow in sequence. Each number is 1 more than the previous numbers.

25, 26 and 27.

Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.

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