Q: Find two numbers whose sum is 36 and such that one is 2 times as large as the other?

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The answer is X-13 + Y- 52 = Sum 65

900 - 30 times 30

The two numbers whose sum is 58 and whose difference is 16 are 21 and 37.

9

Any prime numbers: 3,5,7,11,13,17,19,etc.

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11 & 44

The answer is X-13 + Y- 52 = Sum 65

Let unknown numbers be 2x and x: 2x+x = 24 3x = 24 x = 8 Therefore the two numbers are 8 and 16

33 66+33=99

Let x=smaller #, 4x=larger # x+4x=45 5x=45 Divide both sides by 5. x=9 4x=36

In that case, one of the numbers is a multiple of the other.

That happens when one of the numbers is a factor of the other.

No, because the square of a number is that number times itself, so a no two numbers will have the same square.

900 - 30 times 30

Numbers for which the sum of the digits is divisible by 9. This is also true for 3. There are other divisibility/multiple tests for other numbers (e.g., numbers that are divisible by 5 end in 5 or 0; numbers whose last two digits are divisible by 4 are divisible by 4)

2 and any other even number.

There aren't two prime numbers whose LCM is 90.There aren't two prime numbers whose total is 23.Other than that...The two numbers you are looking for are 5 and 18, but only one of them is prime.