Let unknown numbers be 2x and x:
2x+x = 24
3x = 24
x = 8
Therefore the two numbers are 8 and 16
33 66+33=99
12 and 12, whose squares will be 144 each. If either of the numbers is smaller than 12, then the other will be larger than 12 and its square will be larger than 144.
67
The three numbers are 2, -3, and 6.
prime numbers
11 & 44
1st number=12 2nd number=24
The answer is X-13 + Y- 52 = Sum 65
33 66+33=99
Let x=smaller #, 4x=larger # x+4x=45 5x=45 Divide both sides by 5. x=9 4x=36
That happens when one of the numbers is a factor of the other.
In that case, one of the numbers is a multiple of the other.
No, because the square of a number is that number times itself, so a no two numbers will have the same square.
900 - 30 times 30
Numbers for which the sum of the digits is divisible by 9. This is also true for 3. There are other divisibility/multiple tests for other numbers (e.g., numbers that are divisible by 5 end in 5 or 0; numbers whose last two digits are divisible by 4 are divisible by 4)
2 and any other even number.
There aren't two prime numbers whose LCM is 90.There aren't two prime numbers whose total is 23.Other than that...The two numbers you are looking for are 5 and 18, but only one of them is prime.