Simultaneous equations
A-B=14 (1)
AB=120 (2)
transposing(1) A=14+B
substituting into(2)
B(14+B)=120
B^2+14B =120
B^2+14B-120=0
solve quadratic
(B+20)(B-6)=0
B=-20,6
one of the whole numbers is 6 and the other is 6+14=20
Multiply them together
The product of two whole numbers depends on what the numbers are. The operation is multiplication.11 and 8. You find the factors of 88 first. Then find which 2 will subtract to equal 3
Multiplicand and Multiplier
first add the whole numbers then do simple fraction subtraction
You multiply them. Addition = sum Subtraction = difference Multiplication = product Division = quotient
893 and 907
Multiply them together
Factors.
The product of two whole numbers depends on what the numbers are. The operation is multiplication.11 and 8. You find the factors of 88 first. Then find which 2 will subtract to equal 3
Multiplicand and Multiplier
-2.5 and 2.5
first add the whole numbers then do simple fraction subtraction
six, nine 9 + 6 = 15 (sum) 9 - 6 = 3 (difference) 9 x 6 = 54 (product)
six, seven 7 + 6 = 13 (sum) 7 - 6 = 1 (difference) 7 x 6 = 42 (product)
You multiply them. Addition = sum Subtraction = difference Multiplication = product Division = quotient
12 & 3
The two numbers must be 6 and 9, as 6 + 9 = 15 and theer is a difference of 3 between 6 and 9. The product of 6 and 9 = 54.