Find two consecutive numbers with the value of 4160
What's the question ? Is it to find what the two numbers are ? Since you know their average, you know what the sum of the two numbers is. It's double their average. Now you know their sum, and you know their product. Take the product, and list all of its factors. Find two of the factors that add up to the sum of the two numbers. Those are probably the two numbers you're looking for.
Product = multiply.
The numbers are: 32+29 = 61
"Product" is a binary operation. That means you need two numbers before you can have a product. So 34 does not have a product and so there is no way to find it!
Find two consecutive numbers with the value of 4160
When the two numbers are relatively prime (their GCF is 1), their LCM is their product.
You need at least two numbers to find a product.
Two or more numbers are needed to find their product
17 and 26
It is a positive.
Let the first even number be represented by (2x), where (x) is an integer. The next consecutive even number would then be (2x + 2). The product of these two numbers is (2x(2x + 2) = 4x^2 + 4x). Setting this equal to 840 gives us the quadratic equation (4x^2 + 4x - 840 = 0). Solving this equation yields (x = 10) and (x = -21), but since we are dealing with even numbers, the two consecutive even numbers are 20 and 22.
What's the question ? Is it to find what the two numbers are ? Since you know their average, you know what the sum of the two numbers is. It's double their average. Now you know their sum, and you know their product. Take the product, and list all of its factors. Find two of the factors that add up to the sum of the two numbers. Those are probably the two numbers you're looking for.
220
Two or more numbers are needed to find their product in multiplication.
Two or more numbers are normally needed to find the product
Product = multiply.