9338
Imaginary numbers are only ever used when you are using the square roots of negative numbers. The square root of -1 is i. You may find imaginary numbers when you are finding roots of equations.
If you must use all digits precisely once then the answer is: 8642, 8624, 8462
Assuming the question requires the biggest number formed using the given digits - rather than applying mathematical operations to them - the answer is 76430.
arg_cnt=$# arg_list=$* biggest=$1 if [ $arg_cnt -eq 0 ]; then echo "$RF there should be minimum 1 argument" exit 1 fi for each_arg in $arg_list do if [ $each_arg -gt $biggest ]; then biggest=$each_arg fi done echo " Biggest number is : $biggest \n" exit 0
You can only do this if the two numbers won't be equal: if(a > b) return a; else return b;
Finding the difference between two numbers involves rationalising them
The single biggest cause of car accidents while using a cell phone - is cell phones.
9338
yes
If there are no numbers to divide - not even 1 - then you have made a mistake.
#include <iostream> using namespace std; template <typename T1, typename T2> T1 biggest(T1 x, T2 y) { if(x > y) { cout << "x is biggest" << endl; } else if(y > x) { cout << "y is biggest" << endl; } else { cout << "x & y is equal" << endl; } } int main() { biggest(1.3, 6); char wait; cin >> wait; return 0; }
If you use the "list the multiples" method of finding the LCM, it is likely that the lists and the size of the numbers on the list will increase as the numbers you are comparing get larger. If you learn the "prime factorization" method, you can avoid that.
"Finding the median of a group of numbers usually isn't very challenging"
largest number a,b,c,d
With printf.Example:for (i=0; i
Imaginary numbers are only ever used when you are using the square roots of negative numbers. The square root of -1 is i. You may find imaginary numbers when you are finding roots of equations.