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The area of any triangle is: 0.5*base*perpendicular height
You would use this: ┴
The answer in 6.... draw an angular bisector from one of the angles to the centre of circle then draw a perpendicular from the centre of circle. Those to lines will form a triangle... use trigonometry and find the length of the perpendicular, which is also a radius... double the radius and u will get the diagonal for the square... using formula :- (Side)^2 + (Side)^2 = (Diagonal)^2, find the side of square and square the answer, which will give you your final answer
Raise a perpendicular from one arm to the other. This creates a right angled triangle. Measure two of the sides of the triangle and use the appropriate trigonometric ratio and a computer/calculator/slide rule/tables to convert the ratio to an angle. eg measuring the side adjacent to the angle and the length of the side opposite the angle, which is the perpendicular raised, dividing the length of the opposite side by the adjacent side gives a value which can be looked up in arc tan tables (etc) to get the angle.
(I am going to assume you are higher or in grade 9 math) So use the y=mx + b Use the negative reciprocal of the "m"(slope) part. Do this by simply flipping the fraction. This slope will be perpendicular to the original formula.