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d=(Iv)t+1/2(a)t2

or distance is equal to initial velocity times time plus one half the product of acceleration and time squared

Added:

At linear velocity:

d=r.t

r=rate

t=time

Free fall from rest, starting rate = 0

d=0.5g.t2

g=acceleration due to gravity (mean value on earth: 9.8 m/s2)

t=time

Combined:

d= ro.t + 0.5g.t2

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