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The calculation for normality isn't too hard, but you have to have some info before you can find it.

You need

1 the number of equivalents.

# mol * (subscript on first element of first compound/ number of that element are in the balanced equation) = # equivalents

I am probably confusing you on finding equivalents, but there is not much else I can do. sorry

Using 0.2489 g. of H2C2O4*2H20

is .00197mol so...

.00197 * (2/1) = 3.94*10^-3 equvialents

2 The volume in liters

# mL/1000 = #L

say 43 ml / 1000 +.043 L

so normality would be

(3.94*10^-3)/ .043 = 9.16*10^-2 as normality.

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14y ago

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