Give an numeric example of slip gauge with problem table with range and steps used?

Answer 1

If the dimension to be arranged is 58.975 mm.

Always start with the last decimal place e.g., here it is 0.005 mm and for this 1.005 mm slip gauge is selected.

Now dimension left is 50.975-1.005 = 57.970 mm.

Take second decimal place ; and for it select 1.47 mm slip gauge.

Therefore, the remainder is 57.970 - 1.47 = 56.500 mm.

[Note: One could have selected 1.07 mm piece also, but that way we would have been left with 56.900 and for it we need another 1.4 mm piece. The aim should be to choose minimum number of slip gauges for a given dimension.]

Next for 56.500 mm, we choose 6.500 mm piece and finally 50.000 mm piece.

So, Totally,

50.000 + 6.500 + 1.47 + 1.005 = 58.975 mm

M112 set has

Range mm

Steps mm

Pieces

1.001 to 1.009

0.0001

9

1.010 to 1.490

0.010

49

0.50 to 24.50

0.050

49

25, 50, 75, 100

25

4

1.0005

-

1

Total 112