Graph the line described by the equation -x plus 5y equals 10?

Answer 1

Simplest way to graph a line like this is on a normal x-y axis. (y vertical, x horizontal)

Two methods for drawing the graph

# Use the equation to find the value of y when x is zero, and the value of x when y is zero. Plot the two points on the graph (the will be on the axis lines). Then draw a straight line through them. ---- # Rearrange the equation to find y in terms of x e.g. in the form y = mx +c where m and c are numbers. Plot the point (0,c) and then plot another point say at x = 1 (1,m+c). Then draw a straight line through both points. In is example:

-x + 5y = 10

when x = 0, 5y = 10 or y = 2

when y = 0, -x = 10 or x = -10

plot the two points (0,2) and (-10,0) and then draw a straight line between them.

Sometimes its hard to do this method as if your axis don't go up to -10 the graph will be hard to draw.

or

=> -x+5y = 10

=> 5y = x + 10

=> y = x/5 + 1/2

plot (0,1/2) and say (1,7/10) and draw the straight line through those points