The equation 2x - 3y = 6 is a linear equation and a linear equation is always has a straight line as a graph
It would look like a straight vertical line, i.e. parallel to the y-axis, passing through the point on the x-axis where x=3.
A graph of an equation (or function) helps to clarify the behavior of that equation. In this case, the behavior of the graph is just that: it describes how something acts-- for example:Whether it is a straight line or a bending curveHow many times it changes direction and whereWhether the y-value becomes greater or smaller (moves up or down), or stays constant, as it moves from left to rightIf it is discontinuous (skips around without warning, turns sharply, flies up into infinity for a while, or simply vanishes for a short time)What the equation must look like, such as a line for a linear equation (y = mx + b) or a parabola for a quadratic equation (y = ax2 + bx + c)When the equation crosses the x-axis, something that is very useful to know in Algebra and later mathematicsHow fast the equation is increasing or decreasingIn Calculus, a graph can be used to find the derivative of a function, which is a new function that describes the slope of a function at each pointIn general, a graph is a very useful tool to understand how an equation works, and can make encounters with new and unfamiliar forms of equations easier to understand.
If the equation were to be rearranged so that Y is the subject, it would look like this: Y = V/PS
Well, isn't that just a happy little equation we have here! To solve for x, we can divide both sides by 12, which gives us x equals 2. And just like that, we've found the value of x that makes our equation balanced and complete. Keep up the good work, friend!
Break the question down into two separate equations: Y >= -3 and x >= 6. The graph for the first equation looks like a horizontal line going through point (0,-3) with all of the space above the equation shaded in. The line is a solid line in the solution of equation #1. For equation #2 (x>=6) the graph would look like a solid vertical line that goes through point (6,0). Everything to the right of the line would be shaded in. The system of inequalities would be everything that includes both of these shaded areas or the area in which these two inequalities intercept. So everything shaded that is in both of these inequality equations colors would be the answer - including any point that may be on either line.
The equation is y=x(x+1)(x-2)2
the question does not make sense to make a graph; you need an equation, that means there must be an equals sign. (or an ordering, that means using a greater than sign like this > or a less than sign like this< )
The line 8x-8=0 is the same as x=1. The graph looks like a vertical line that intersects the x axis at x=1.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
A line graph needs an equation. x-2 and x3 are expressions: neither is an equation.
A linear function is a function whose graph is a straight line.
It looks like this came from some multiple choice question, where you're given several choices. Take each choice and substitute the x and y coordinates into the equation. So for example the point is (0,3), then substitute in and get 2*0 + 3 which equals 3 and satisfies the equation, so the point is on the graph. If the point is (1,1) then 2*1 + 1 = 3 which satisfies the equation, so that point is also on the line. You want to find one where the left side does not equal 3, then that point is not on the graph of the line.
You get a straight line (parallel to the x-axis) that passes through only the y-axis, and it crosses the y-axis at (0,3)
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
It would look like a straight vertical line, i.e. parallel to the y-axis, passing through the point on the x-axis where x=3.
its a simple parobola symmetric about y axis, having its vertex at (0,-4). we can make its graph by changing its equation in standard form so that we can get its different standard points like vertex, focus, etc.
The picture of the graph is in the related links section.