The equation 2x - 3y = 6 is a linear equation and a linear equation is always has a straight line as a graph
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It would look like a straight vertical line, i.e. parallel to the y-axis, passing through the point on the x-axis where x=3.
A graph of an equation (or function) helps to clarify the behavior of that equation. In this case, the behavior of the graph is just that: it describes how something acts-- for example:Whether it is a straight line or a bending curveHow many times it changes direction and whereWhether the y-value becomes greater or smaller (moves up or down), or stays constant, as it moves from left to rightIf it is discontinuous (skips around without warning, turns sharply, flies up into infinity for a while, or simply vanishes for a short time)What the equation must look like, such as a line for a linear equation (y = mx + b) or a parabola for a quadratic equation (y = ax2 + bx + c)When the equation crosses the x-axis, something that is very useful to know in Algebra and later mathematicsHow fast the equation is increasing or decreasingIn Calculus, a graph can be used to find the derivative of a function, which is a new function that describes the slope of a function at each pointIn general, a graph is a very useful tool to understand how an equation works, and can make encounters with new and unfamiliar forms of equations easier to understand.
If the equation were to be rearranged so that Y is the subject, it would look like this: Y = V/PS
Well, isn't that just a happy little equation we have here! To solve for x, we can divide both sides by 12, which gives us x equals 2. And just like that, we've found the value of x that makes our equation balanced and complete. Keep up the good work, friend!
Break the question down into two separate equations: Y >= -3 and x >= 6. The graph for the first equation looks like a horizontal line going through point (0,-3) with all of the space above the equation shaded in. The line is a solid line in the solution of equation #1. For equation #2 (x>=6) the graph would look like a solid vertical line that goes through point (6,0). Everything to the right of the line would be shaded in. The system of inequalities would be everything that includes both of these shaded areas or the area in which these two inequalities intercept. So everything shaded that is in both of these inequality equations colors would be the answer - including any point that may be on either line.