Open dot at 4 and a line going to the left on the number line.
graph x+4<5
The second graph is shifted upwards by 4 units.
if 2y-x=4, than y=1/2*x+2 we can now see that the graph is linear with slope 1/2 and goes through point (0,2)
You subtract X from both sides, in which u get y=x-4; u should be able to graph that
First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)
graph x+4<5
The second graph is shifted upwards by 4 units.
A graph with x and y coordinates has 4 quadrants, so would be a 4 quadrant graph.
if 2y-x=4, than y=1/2*x+2 we can now see that the graph is linear with slope 1/2 and goes through point (0,2)
You subtract X from both sides, in which u get y=x-4; u should be able to graph that
use a line graph. Place a solid dot at 4. Shade the entire region to the left of 4.x is Less than shade Left.* * * * * The above answer is so very wrong - it has missed out the key word "absolute".Use a line graph. Put a solid dot at -4 and another solid dot at +4 and join them. Every point on the line (including the two end points) is the graph.
First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)
4x<4 means x<1 If you graph this on the number lines, you need an open circle at 1 and a solid line from 1 going to the left forever.
If x is less than one, the graph will be a number line with every point less than (but not including) 1 shaded.If x is greater than one, the graph will be a number line with every point greater than (but not including) 1 shaded.
To reflect the graph of ( f(x) = x - 1 ) across the y-axis, you replace ( x ) with ( -x ), resulting in the equation ( f(-x) = -x - 1 ). To translate this graph 4 units down, you subtract 4 from the entire function, giving you ( f(-x) - 4 = -x - 1 - 4 = -x - 5 ). Thus, the final transformed function is ( f(-x) - 4 = -x - 5 ).
It is translated left 8 and up 4.
Domain is considered the x-axis. So, to find the domain, one should to read the graph from left to right.