y = 2x + 1 1. Make a table: x = -2; y = -3
y = 2x + 1
y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1
y = 2x + 1
y = 2(-1) + 1 = -2 + 1 = -1
x = 0; y = 1
y = 2x + 1
y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3
y = 2x + 1
y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5
y = 2x + 1
y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1
-2x plus 3y equals 1
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
NM equals 2x + 1, as stated in the question!
The answer to 1 over 2x plus 13 equals 9 is x equals -8.
2x + 6y = 6Subtract 2x from each side:6y = -2x + 6Divide each side by 6:y = -1/3 x + 1The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].
-2x plus 3y equals 1
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
A graph that has 1 parabolla that has a minimum and 1 positive line.
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
1
x=1
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
x = 0
y=-10x-4
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
NM equals 2x + 1, as stated in the question!
Y = 2x + 1