y = 2x + 1 1. Make a table: x = -2; y = -3
y = 2x + 1
y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1
y = 2x + 1
y = 2(-1) + 1 = -2 + 1 = -1
x = 0; y = 1
y = 2x + 1
y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3
y = 2x + 1
y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5
y = 2x + 1
y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1
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-2x plus 3y equals 1
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
NM equals 2x + 1, as stated in the question!
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2x + 6y = 6Subtract 2x from each side:6y = -2x + 6Divide each side by 6:y = -1/3 x + 1The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].