Suppose the angle is x degrees.
Then its supplement is 180-x. One-third its supplement is (180-x)/3 = 60-x/3
so x/2 = 60-x/3+25
5x/6 = 85 ie x = 102.
supplement + angle = 180180 - angle = supplementangle = supplement + 40 = 180 - angle +40 = 220-angle2 x angle = 220angle = 110 degrees
The supplement of an angle is found by subtracting the angle from 180 degrees. For angle B, which measures 32 degrees, the supplement can be calculated as follows: 180 - 32 = 148 degrees. Therefore, the measure of the angle supplement of B is 148 degrees.
Complement of a given angle = (90 - given angle) Supplement of a given angle = (180 - given angle)
116 degrees
The supplement of an angle is found by subtracting the angle from 180 degrees. Therefore, the supplement of a 32-degree angle is 180 - 32 = 148 degrees.
The angle is 105, its supplement is 75.
supplement + angle = 180180 - angle = supplementangle = supplement + 40 = 180 - angle +40 = 220-angle2 x angle = 220angle = 110 degrees
The angle= 36, the supplement= 144, the compliment=54
Suppose the angle is x then its supplement is 180 - x so 180 - x = x - 78 that is, 258 = 2x or x = 258/2 = 129 <><><><><> Angle + Supplement = 180 Angle = Supplement + 78 Solve for the system of equations... Angle + Supplement = 180 Angle - Supplement = 78 ------------------------------------- 2 Angle = 258 Angle = 129 Supplement = 51
60o is the supplement to an angle of 120o
25
The supplement of an 80 degree angle is an 100 degree angle.
The supplement of an angle is found by subtracting the angle from 180 degrees. For angle B, which measures 32 degrees, the supplement can be calculated as follows: 180 - 32 = 148 degrees. Therefore, the measure of the angle supplement of B is 148 degrees.
179 degrees
Complement of a given angle = (90 - given angle) Supplement of a given angle = (180 - given angle)
116 degrees
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