27
if the last two digits are lesser than 50 (e.g. 8634), you round down by making the last two digits 0 (in this case, 8600).If the last two digits are greater than 50 (e.g. 8662), you round up by adding 1 to the hundreds and making the last two digits 0 (in this case, 8700).If the last two digits are exactly 50, you can round up or down, your choice.
Exactly as in the question.
Any pair of digits (not including 0), can be used to generate 14 four-digit numbers. If one of the digits is 0, only seven will start with a non-zero digit.
900
One: 444!
There are 27 of them.
90
Exactly 19 of them
Assuming that 001, 080, etc are not allowed (that is a leading zero or two is not permitted), the smallest number with exactly three digits is 100. The largest number with exactly three digits is 999. So there are 999 - 100 + 1 = 900 numbers with exactly three digits.
Exactly 32 of them
To determine if 29380 is exactly divisible by 4, we need to check if the last two digits of the number form a multiple of 4. In this case, the last two digits are 80, which is indeed a multiple of 4. Therefore, 29380 is exactly divisible by 4.
Yes, they have almost exactly the same dimensions, but the 4S is a bit heavier.
27
Are the last two digits of the year divisible exactly by 4? If the last two digits are"00" are the first two digits divisible exactly by 4? I believe that in Russia "00" Leap Years are those which leave a remainder of 2 or 6 when the first two digits are divided by 9. This is actually more accurate than the system with which most of the rest of the world is familiar and was originated by the Greek Orthodox Church.
Its Exactly 10 Rupees
if the last two digits are lesser than 50 (e.g. 8634), you round down by making the last two digits 0 (in this case, 8600).If the last two digits are greater than 50 (e.g. 8662), you round up by adding 1 to the hundreds and making the last two digits 0 (in this case, 8700).If the last two digits are exactly 50, you can round up or down, your choice.