-2x3-2x2+12x
(-2)(x3+x2-6x)
(-2x)(x2+x-6)
(-2x)(x2+3x-2x-6)
(-2x)((x)(x+3)-2(x+3))
(-2x)((x-2)(x+3)
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To factor the trinomial ( x^2 - 12x + 35 ), we need to find two numbers that multiply to 35 and add to -12. The numbers -5 and -7 satisfy these conditions. Therefore, the trinomial can be factored as ( (x - 5)(x - 7) ), and one of the binomial factors is ( x - 5 ).
If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)
x^(3) - 12x^(2) + 35 x Factor out 'x' Hence x(x^(2) - 12x + 35) Factor the quadratic x(x - 5)(x - 7) Done!!!!!
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored