-2x3-2x2+12x
(-2)(x3+x2-6x)
(-2x)(x2+x-6)
(-2x)(x2+3x-2x-6)
(-2x)((x)(x+3)-2(x+3))
(-2x)((x-2)(x+3)
If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)
x^(3) - 12x^(2) + 35 x Factor out 'x' Hence x(x^(2) - 12x + 35) Factor the quadratic x(x - 5)(x - 7) Done!!!!!
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
-2x(x + 3)(x + 2)
-2x(x + 3)(x + 2)
If you mean: x2-12x+35 then it is (x-7)(x-5) when factored
I would do this. Multiply through by -1 -1 ( -X^2 +12X +28 ) = X^2 -12X -28 (X+2)(X-14)
If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)
The list of choices that you posted with your question doesn't include any factor of that expression.
x^(3) - 12x^(2) + 35 x Factor out 'x' Hence x(x^(2) - 12x + 35) Factor the quadratic x(x - 5)(x - 7) Done!!!!!
Jjg
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
8x2 - 12x - 8 = 4 (2x2 - 3x - 2) = 4 (2x2 + x - 4x - 2) = 4 (x (2x + 1) - 2 (2x + 1)) = 4 (x - 2) (2x + 1).
-2x(x + 3)(x + 2)
-2x(x + 3)(x - 2)