-2x(x + 3)(x + 2)
2x^2
-x2 + 2x + 48 = (-x - 6)(x - 8)
To factor the trinomial (7x^2 + 7x - 14), first factor out the common factor of 7: [ 7(x^2 + x - 2) ] Next, we can factor the quadratic (x^2 + x - 2) into ((x + 2)(x - 1)). Thus, the complete factorization of the original trinomial is: [ 7(x + 2)(x - 1) ]
2x2 + 15x + 25 = (2x + 5)(x + 5)
3x2 + 36x + 81 = 3(x2 + 13x + 27)
-(x + 13)(x - 2)
-(3x - 4)(x - 2)
(x + 5)(x - 8)
-(3x+4)(x+2)
(x + 7)(x - 6)
x(x - 1)(x - 13)
It is (x - 9)*(x + 4)
x(x + 5)(x - 7)
x(x - 4)(x - 6)
2x^2
It will be difficult to answer this question accurately without knowing "the expression below."
It is: (x2 + 5x) (x + 8)