-2x(x + 3)(x + 2)
2x^2
-x2 + 2x + 48 = (-x - 6)(x - 8)
To factor the trinomial (7x^2 + 7x - 14), first factor out the common factor of 7: [ 7(x^2 + x - 2) ] Next, we can factor the quadratic (x^2 + x - 2) into ((x + 2)(x - 1)). Thus, the complete factorization of the original trinomial is: [ 7(x + 2)(x - 1) ]
4c^2-12c+9 is a trinomial because it is in the form of ax^2 + bx + c. In this case, the trinomial is a perfect square trinomial. 4c^2-12c+9 =(2c-3)(2c-3) =(2c-3)^2
2x2 + 15x + 25 = (2x + 5)(x + 5)
(x + 5)(x - 8)
-(3x - 4)(x - 2)
-(x + 13)(x - 2)
It is (x - 9)*(x + 4)
x(x + 5)(x - 7)
x(x - 1)(x - 13)
x(x - 4)(x - 6)
(x + 7)(x - 6)
2x^2
(-4x + 3)(x - 2)Apex :)!!
x(x + 4)(x + 6)
It will be difficult to answer this question accurately without knowing "the expression below."