99 ÷ 9 = 11
99 of them with a remainder of 9
You can get eleven 9s from 99. This is because when you take 99 and divide it by 9, the result is 11. Thus, 99 contains eleven instances of the digit 9.
Eleven (11)
11
An infinite number of ways. 99+9/9 (99+9/9)*9/9 (99+9/9)*99/99 (99+9/9)*999/999 (99+9/9)*9/9*9/9 etc
99 ÷ 9 = 11
11 times 9=99.
99
99 of them with a remainder of 9
You can get eleven 9s from 99. This is because when you take 99 and divide it by 9, the result is 11. Thus, 99 contains eleven instances of the digit 9.
The answer is 6.99574217 × 1013
9
Eleven (11)
There are infinitely many solutions to 11x - 99 = 11(x - 9)
9 - 9 + 9 / 9 + 99 = 100solution:9 - 9 = 00 + 9 = 99 / 9 = 11 + 99 = 100A more simple approach might be 99-(-99/99) which simplifies to 99+1=100.
The LCM of 9 and 99 is 99.