#include <iostream> int main() { std::cout << "1 121 12321 1234321" << std::endl; return 0; }
21 The pattern is 121, 12321, 1234321
121, 484, 12321, 1234321, 123454321, 12345654321, 1234567654321, 123456787654321, 1234567897654321, 1002001, 10201, 100020001, 10000200001, 1000002000001
A number that reads the same backwards as it does forwards. For example 1357531, or 121.
Palindromic numerical sequences are series of numbers that read the same when read either forward or backward, such as: 6 121 474 12321 22522 459878954
#include <iostream> int main() { std::cout << "1 121 12321 1234321" << std::endl; return 0; }
21 The pattern is 121, 12321, 1234321
121, 484, 12321, 1234321, 123454321, 12345654321, 1234567654321, 123456787654321, 1234567897654321, 1002001, 10201, 100020001, 10000200001, 1000002000001
A number that reads the same backwards as it does forwards. For example 1357531, or 121.
Palindromic numerical sequences are series of numbers that read the same when read either forward or backward, such as: 6 121 474 12321 22522 459878954
To print the given pyramid pattern in C, you can use nested loops. The outer loop controls the rows, and the inner loop controls the numbers to be printed in each row. Here's a simple C program to achieve this: #include <stdio.h> int main() { int rows = 5; for (int i = 1; i <= rows; i++) { for (int j = 1; j <= i; j++) { printf("%d", j); } for (int j = i - 1; j >= 1; j--) { printf("%d", j); } printf("\n"); } return 0; } This program will output the desired pyramid pattern.
No
1x1=1 11x11=121 111x111=12321 1111x1111=1234321 11111x11111=123454321 There is another 11 trick. 11 *11 ok so you always put the 11 on top. Then the number on the bottom. The first digit goes on the left. then leave a space for the middle number. Then the second digit and put it in the right spot. Then add those together and put that numbe rinto the middle spot! ----- 121
#include#includevoid main(){clrscr();for (int i=1;i
121 cubed = 121 x 121 x 121 = 1,771,561
121 multiplied by 121 is 14,641.
121