90, 91, 92, 93, 94, 95, 96
90, 91, 92, 93, 94, 95, 96That's the only set of seven consecutive composite numbers less than 100.
First, multiply the consecutive numbers. Your total will be the highest factor.
The only number set that fits these criteria are, 90, 91, 92, 93, 94, 95, 96.
Nine of them. All consecutive integers have nine tenths between them.
42 and 84
90, 91, 92, 93, 94, 95, 96That's the only set of seven consecutive composite numbers less than 100.
First, multiply the consecutive numbers. Your total will be the highest factor.
The only number set that fits these criteria are, 90, 91, 92, 93, 94, 95, 96.
help
Nine of them. All consecutive integers have nine tenths between them.
42 and 84
2/5 are prime, 8/15 are composite (and 1/15 is neither).
122, 123, 124, 125, 126. The only way for the mean of 5 consecutive numbers to be 124 is if the median is also 124.
To write a composite number as a product of two prime numbers, write it as an answered multiplication question like 2 x 17 = 34 or 3 x 3 x 7 = 63.
15 and 16
Let's denote the three consecutive numbers as x, x+1, and x+2. Since the sum of these three numbers is 150, we can write the equation x + (x+1) + (x+2) = 150. Simplifying this equation gives us 3x + 3 = 150. Solving for x, we get x = 49. Therefore, the three consecutive numbers are 49, 50, and 51.
I'm not sure what you mean. But the factorization of a composite number into prime factors is unique, up to the ordering of the primes.