Opposite faces sum to 21.
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Eight numbers.
The question is underspecified since the answer depends on the numbers on the dice. If all the numbers on both the dice are the same, there is clearly only one outcome. If the dice have 4 different numbers, then there can be 16 different outcomes. If the numbers on each die are 1,2,3 and 4 (or any four numbers in arithmetic sequence) there will be 7 outcomes.
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
Odd prime numbers on a dice are 3 and 5.
There is a one out of four chance of having both dice even numbers.