v = 30 x 30x5 = 4500 cu ft
(2000 sq. ft.) X (1 in.) X (1 ft. / 12 in.) = 167 cu. ft.(167 cu. ft.) X (1 cu. yd. / 27 cu. ft.) = 6.2 cu. yd.Full size pickup truck will hold 2 to 3 cu. yd.Tandem axle box truck will hold 10 cu. yd.
1 foot
At an average of about 30 lbs per cubic foot, that is about 20/30 = 2/3 cubic feet. A little less if wet, about 1 cu ft if really dry
Volume is 30 x 20 x 1/6 ie 100 cu ft. 27 cu ft make one cu yd so 100/27 ie 3.7 cu yds to one significant figure.
v = 30 x 30x5 = 4500 cu ft
If the units are 30 ft x 30 ft x 4 inches, then you have 30 x 30 x 0.33 ft = 300 cubic feet300 cubic ft/27 cu yds/cu ft = 11.1 cubic yards
(2000 sq. ft.) X (1 in.) X (1 ft. / 12 in.) = 167 cu. ft.(167 cu. ft.) X (1 cu. yd. / 27 cu. ft.) = 6.2 cu. yd.Full size pickup truck will hold 2 to 3 cu. yd.Tandem axle box truck will hold 10 cu. yd.
1 foot
Diameter= 60 ft. Radius = 30 f. Depth = 12 ft. Area = PI * r^2 (sq. ft.) = PI*30^2 = 2827.4 sq. ft. Volume = (Area * Depth)/2 (cu. ft.) = 16964.6 cu. ft. =Volume (cu. ft.) * 0.13368 cu.ft./gal >>(gallons) = 126890.6 gallons
360 cu ft or if the "4" is inches, not feet, one twelfth of that, ie 30 cu ft
The answer is specific to the product in the cu ft. A cu ft of water will be different than that of a cu ft of feathers ETC.
The answer depends on the thickness of the covering layer.
12 in = 1 ftradius = diameter ÷ 2Assuming those are internal dimensions, the volume of the pool is:volume = π x radius2 x depth= π x (12 ft ÷ 2)2 x (30 ÷ 12) ft= 90π cu ft≈ 282.74 cu ftConversion to gallons depends upon which gallon you're using:1 cu ft ≈ 6.23 imperial gallons → 282.74 cu ft ≈ 1761.16 imp gallons1 cu ft ≈ 7.48 US gallons → 282.74 cu ft ≈ 2115.07 US gallons
.07 (No. That is incorrect.) Actually there are 27 cu ft in a cu yard or .037 cu yards in a cu ft.
At an average of about 30 lbs per cubic foot, that is about 20/30 = 2/3 cubic feet. A little less if wet, about 1 cu ft if really dry
.1337 cu ft / gal 7.481 gal / cu ft