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IMPROVED:

A simpler way us to simply use a binary number scheme. As we know, in base-10 (normal numbers) each digit up is higher than the last by one factor. IE, 1's, 10's, 100's, 1000's.

The same is true in Binary, but with factors of 2, not 10. Here's an example of each number and it's placement:

0------0------0------0------1------0------0------0

128s-64a--32s---16s----8s----4s-----2s----1s

So, in 8-bit binary, the number 8 woul be 00001000 9or just 1000

OLD:

For converting any decimal number into binary a simple procedure is applied. Step 1. Divide the number with the base of binary number which is 2.

Step 2. Remember the remainder either it is 1 or 0.

Step 3. Divide again the answer of the number and remember the remainder.

Keep dividing the answer and remembering the remainder until number is totally divided.

Now put the last remainders in a series, in LIFO style.

mean the remainder derive last put it into first.

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