They are simply referred to as local minimums and maximums. Experience: Algebra 2 Advanced
Suppose you have a quadratic function of the form y = ax2 + bx + c where a, b and c are real numbers and a is non-zero. [If a = 0 it is not a quadratic!] The turning point for this function may be obtained by differentiating the equation with respect to x, or by completing the squares. However you get there, the turning point is the solution to 2ax + b = 0 or x = -b/2a Now, if a > 0 then the quadratic has a minimum at x = -b/2a and it has no maximum because y tends to +∞ as x tends to ±∞ . if a < 0 then the quadratic has a maximum at x = -b/2a and it has no minimum because y tends to -∞ as x tends to ±∞. You evaluate the value of y at this point. y = a(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c = -(b2 - 4ac)/4a In either case, if the domain of the function is bounded on both sides, then the missing extremum will be at one or the other bound - whichever is further away from (-b/2a).
A quadratic can be drawn as a graph and it is either "U" shaped or "n" shaped. If it were "U" shaped, the minimum value qould be the lowest point of the "U". If "n" shaped, maximum would be the top.
...i need the answer to that too...
A global minimum is a point where the function has its lowest value - nowhere else does the function have a lower value. A local minimum is a point where the function has its lowest value for a certain surrounding - no nearby points have a lower value.
It can't - unless you analyze the function restricted to a certain interval.
vertex
Apex.
By taking the derivative of the function. At the maximum or minimum of a function, the derivative is zero, or doesn't exist. And end-point of the domain where the function is defined may also be a maximum or minimum.
They are simply referred to as local minimums and maximums. Experience: Algebra 2 Advanced
The point on the parabola where the maximum area occurs is at the vertex of the parabola. This is because the vertex represents the maximum or minimum point of a parabolic function.
Suppose you have a quadratic function of the form y = ax2 + bx + c where a, b and c are real numbers and a is non-zero. [If a = 0 it is not a quadratic!] The turning point for this function may be obtained by differentiating the equation with respect to x, or by completing the squares. However you get there, the turning point is the solution to 2ax + b = 0 or x = -b/2a Now, if a > 0 then the quadratic has a minimum at x = -b/2a and it has no maximum because y tends to +∞ as x tends to ±∞ . if a < 0 then the quadratic has a maximum at x = -b/2a and it has no minimum because y tends to -∞ as x tends to ±∞. You evaluate the value of y at this point. y = a(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c = -(b2 - 4ac)/4a In either case, if the domain of the function is bounded on both sides, then the missing extremum will be at one or the other bound - whichever is further away from (-b/2a).
You can detect the brightest point in an image using the minMaxLoc function in OpenCV. This function will return the minimum and maximum pixel intensity values, as well as the coordinates of the minimum and maximum values. By retrieving the coordinates of the maximum value, you can locate the brightest point in the image.
A quadratic can be drawn as a graph and it is either "U" shaped or "n" shaped. If it were "U" shaped, the minimum value qould be the lowest point of the "U". If "n" shaped, maximum would be the top.
The vertex, or maximum, or minimum.
A maximum or minimum is generally referred to as an extrema.
Some do and some don't. It's possible but not necessary.