A rational equation can be multiplied by the least common multiple of its denominators to make it into a polynomial equation. The degree of this polynomial is the highest power (of the variable) that appears in it.
It can be proven that a polynomial of degree n must have n roots in the complex domain. However, there may be fewer roots in the real domain. This is because if the coefficients are real then there may be pairs of complex roots [conjugates] which will not count as real roots. Also, there may be identical roots of multiple order. For example,
x4 - 1 = 0 has 4 complex roots. These are 1, -1, i and -i where i is the imaginary root of -1.
There are only 2 real roots -1 and +1.
x4 = 0 has 4 multiple roots, each of which is 0. Thus x = 0 is a root of multiplicity 4.
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Not all rational equations have a single solution but can have more than one because of having polynomials. All rational equations do have solutions that cannot fulfill the answer.
YES
Yes and sometimes it can have more than one solution.
True
yes, if it is in brackets and the equation is doubled. (These are the words of my grade 12 teacher)