93 and 42
89 x 90 = 8010 which are two consecutive two digit numbers that equal 8010.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
1348.
There are five such numbers.
Write them as decimals, and compare. If the first digit of two numbers is equal, compare the second digit; if the second digit is equal, compare the third digit, etc.
93 and 42
Two (or four) digits added together cannot equal 42. Two-digit numbers multiplied together cannot equal 82.
2,4,6,8,10,12,14,16,18
89 x 90 = 8010 which are two consecutive two digit numbers that equal 8010.
70 and 90
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
25 and 36 are each equal to their rightmost digit squared. 25 = 5 X 5 36 = 6 X 6
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
There are no three-digit numbers that equal 17. In fact, there are no numbers with more or less than two digits that equal 17. In fact, in the whole infinite supply of numbers, there is only one single number that equals 17. That number is . . . . . . . 17 .
1348.