One of them is twelve and the other is a dozen. They both equal 12.
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93 and 42
89 x 90 = 8010 which are two consecutive two digit numbers that equal 8010.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
1348.