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The same as the number of two-digit numbers, since the last two digits

must the same as the first two, only reversed.

So I'll say there are 100 four-digit palindromes.

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Q: How many four digit palindromic numbers are there?

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899100 of them. Only 900 of the 900000 are palindromic.

9,000

500 or so.

625 if numbers can have leading 0s, 500 otherwise.

The numbers from 1000 to 9999 are all 4 digits, as are -1000 to -9999. Therefore there are 18,000 four-digit numbers in all.

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There are 90 palindromic numbers.

9

90

There are 900000 of them.

The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.

899100 of them. Only 900 of the 900000 are palindromic.

40. Excluding numbers starting with 0.

A palindromic number can have as few as one digit, and as many as infinity. The smallest palindromic number is zero and the largest is '999... to infinity'.

There is: 101,111,121,131,141,151,161,171,181,191 202,212,222,etc... 999 There are 90 palindromic 3 digit numbers

a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321 so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999, so there are 8999 palindromic 8 digits number (I assumed that 00011000 is not to be considered as a valid 8 digit number)

1 to 1000. Pilandromic 108

To be a 3 digit palindromic number, it must be of the form aba.I assume that a 3 digit number must be at least 100 (so that 020 for example does not count as a 3 digit number):a can be any of the nine digits 1-9;for each of these b can be any of the ten digits 0-9Thus there are 9 x 10 = 90 three digit palindromic numbers.

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