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You put the numbers in order from least to greatest then, start at the beginning and end, and cross out one... two... three... four..., then so on, until you have only one number in the middle.
Example 27,44,45,46,52; cross out 27, then... 52, then... 44, then... 46, then... 45 is the last answer left, so 45, is your answer.
man, whoever answered this question is a total fool. they wanted to know how to find the median of GROUPED DATA not just the median.
wow what a fool.
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Median formula for grouped data?
Simple answer:Divide the total number of observations (plus 1, if small) by 2 to find the middle rank.Look at the cumulative frequencies for the grouped data and find the group in which the middle rank would appear. That is the median group.More sophisticated answer:Withing the median group, interpolate.
How you can find the median of grouped data graphically?
On the cumulative frequecy diagram, find 50% on the frequency [usually, vertical] axis. Draw a line to the graph and then drop a perpendicular to the other [horizontal] axis. Where it hits the second axis is the median value.
Why it is useful to fiNd the meaN mediaN aNd mode of a set of data?
when there are extreme values in the data
How do find the interquartile range in your data?
Arrange the data in increasing order and count the number of data points = N. Find the integer K = N/2 or (N+1)/2. The Kth number in the ordered set is the median. Now consider only the numbers from the smallest to the median and find the median of this subset. This is the lower quartile = Q1. Then consider only the numbers from the original median to the largest. Find the median of this subset. It is the upper quartile = Q3. Then IQR = Q3 - Q1
How do you find the median with an even data set?
Let the data set be 3,4,5,6,7,8. First put the data in rank order ; already done!!!! To find the MEDIAN , we tak the two middle numbers, '5' & '6' in this case. Then (5 + 6) / 2 = 11/2 = 5.5 5.5 is the Median.
