Simple answer:
Divide the total number of observations (plus 1, if small) by 2 to find the middle rank.
Look at the cumulative frequencies for the grouped data and find the group in which the middle rank would appear. That is the median group.
More sophisticated answer:
Withing the median group, interpolate.
D=E1+((dN/10)-Cf)(I)/F The formula of deciles is different for grouped and ungrouped data.
You put the numbers in order from least to greatest then, start at the beginning and end, and cross out one... two... three... four..., then so on, until you have only one number in the middle. Example 27,44,45,46,52; cross out 27, then... 52, then... 44, then... 46, then... 45 is the last answer left, so 45, is your answer. man, whoever answered this question is a total fool. they wanted to know how to find the median of GROUPED DATA not just the median. wow what a fool.
On the cumulative frequecy diagram, find 50% on the frequency [usually, vertical] axis. Draw a line to the graph and then drop a perpendicular to the other [horizontal] axis. Where it hits the second axis is the median value.
In continuous grouped data the data is collected continuously and in groups. Data collected is in class intervals the actual data values are not visible.
123456789987456321
A frequency diagram or, for grouped data, an histogram.
Mean = a + [
it is used to find mean<median and mode of grouped data
Mean, median and mode are ways to find averages. The mode is the most common answer in a set of data. The median the number that is in the middle when the numbers are put in order. The mean is the statical average.
ungruped data are those type of data which are not proper arranged or order
You will need to put the un-grouped data in ascending or descending order. If you have an odd number of data values the formula for the median value is (n+1)/2. Example my data in ascending order is 0, 2, 4, 5, 7, 8, 9. I have 7 data values. The median is the value (7+1)/2 = 4th value from left or right which is 5. For an even number of data values, you will need to calculate the median and it may not be a data value. It will be the mean of the two center values. Use the formula n/2 to get the left most value. Example my data in ascending order is 0, 2, 4, 5, 7, 8. I have 6 data values. The left most value I will use to calculate the median is 6/2 = 3rd. The 3rd value from the left is 4. The next value is 5. Median is (4+5)/2 = 4.5.
Mean and median are the measures of central location that always have one value. This is true for a set of grouped or ungrouped data.
Not sure what a "grouped of data" means!
D=E1+((dN/10)-Cf)(I)/F The formula of deciles is different for grouped and ungrouped data.
L + d1/d1+d2 x w
You put the numbers in order from least to greatest then, start at the beginning and end, and cross out one... two... three... four..., then so on, until you have only one number in the middle. Example 27,44,45,46,52; cross out 27, then... 52, then... 44, then... 46, then... 45 is the last answer left, so 45, is your answer. man, whoever answered this question is a total fool. they wanted to know how to find the median of GROUPED DATA not just the median. wow what a fool.
The formula for calculating median on grouped data is L + I *(50% * N-F)/f L - lower limit of the median group I - group interval N - Number of frequency (total sum of frequencies in each group) F - cumulative freqency for the group before the median group f - frequency of the median group Since median is just the same as the 2nd quartile, we use 0.5 in place of 50% in the formula. We can tweak the formula a little bit to calculate any percentile. For example, if you want to calculate 35th percentile, change the formula to L + I *(35% * N-F)/f which is L + I *(0.35 * N-F)/f. Please note that L,I,F & f should reflect that of the group where the percentile falls. You can find this by these steps: 1) Calculate N * 0.35. Lets say N=50 then 50* 0.35 = 17.5. 2) Using cumulative frequency, identify the group where 17.5 falls. 3) Use L,I,F & f for that particular group in the formula L + I *(0.35 * N-F)/f