0
Add your answer:
Earn +20 pts
What quadrants the graph of x - y equals 5 is plotted in when graphed?
Quadrants I, III and IV.
What is the amplitude for y equals 5 sin x?
5
What is x if the sin of x equals square root of 5 divided by 2?
2.5
How do you solve y equals -10 sin 5x?
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
Y equals 4 sin x for x equals pi?
sin(pi) = 0 so 4*sin(pi) = 0 so Y = 0
What quadrants the graph of x - y equals 5 is plotted in when graphed?
Quadrants I, III and IV.
What is the amplitude for y equals 5 sin x?
5
When does cos x equal -sin x?
The derivative of cos(x) equals -sin(x); therefore, the anti-derivative of -sin(x) equals cos(x).
What is x if the sin of x equals square root of 5 divided by 2?
2.5
Find the derivative y equals 10 to the sin3x power?
Y=10^sin(x) The derivative is: (log(5)+log(2))*cos(x)*2^sin(x)*5^sin(x) Use the chain rule, product rule, and power rules combined with sin(x) rule.
When are y equals sin x and y equals cos x times cos x equal?
y=sin x y=cos x cos x sin x = cos^2 x sin x = 1-sin^2 x sin x -1 + sin^2 x = 0 sin^2 x + sin x -1 = 0 Let y=sin x y^2+y-1 = 0 This equation is of form ay^2+by+c=0 a = 1 b = 1 c = -1 y=[-b+/-sqrt(b^2-4ac)]/2a] y=[-1 +/-sqrt(1^2-4(1)(-1)]/(2)(1) discriminant is b^2-4ac =5 y=[-1 +√(5)] / 2 y=[-1 -√(5)] / 2 sin x = [-1 +√(5)] / 2 x = sin^-1 [-1 +√(5)] / 2] = 0.6662394 radians x = sin^-1 [-1 -√(5)] / 2] = sin^-1 (-1.618) -- has no solution When x = 0.6662394 radians, sin x and cos x times cos x are equal.
If Sin equals x and Cos equals y then x squared equals what function of y?
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
If sin x - cos x equals 1 over 3 what is sin x?
Sin[x] = Cos[x] + (1/3)
What is the value sin x if cos x equals 2 over sqrt 5?
It would be 1 over square root 5.
1 over sin x equals what?
1/sin x = csc x
How do you graph y2x?
y2x is an expression, which cannot be graphed because we don't know what it equals. y = 2x, y2 = x, and 2y (or y2) = x are all things that could actually be graphed.
Sin x Tan x equals Sin x?
No. Tan(x)=Sin(x)/Cos(x) Sin(x)Tan(x)=Sin2(x)/Cos(x) Cos(x)Tan(x)=Sin(x)
