This is actually quite easy to prove. The Taylor series of the exponential function, e^x (using "^" for power) is 1 + x^1/1! + x^2/2! + x^3/3! + x^4/4! ..., so all you need to do is replace the exponent "x" by 1.
(To be precise, you would also have to prove that the corresponding Taylor series is correct - that means proving that the residual tends towards zero. This is the case for most commonly used functions, but it must still be proven for individual cases such as this one.)
Cannot prove that 2 divided by 10 equals 2 because it is not true.
Because there is no way to define the divisors, the equations cannot be evaluated.
There is no mathematical proof that space is infinite. All we know is that there is an expanding limit to what we can see.
a0=(a-1\a-1)=a\a=1
It is extremely difficult to prove things which are not true.
Cannot prove that 2 divided by 10 equals 2 because it is not true.
Because there is no way to define the divisors, the equations cannot be evaluated.
5
What divided by 7 equals 8? In other words, you have an unknown number (X), and then if you divide that X by 7 you get 8. Then what is that X? The equation to calculate what divided by 7 equals 8 is as follows: X/7 = 8 Where X is the answer. When we solve the equation by multiplying each side by 7, you get get: X = 56 Therefore, the answer to what divided by 7 equals 8 is 56.
There is no mathematical proof that space is infinite. All we know is that there is an expanding limit to what we can see.
You can't it equals 2. You can't it equals 2.
No you can not prove that 9 +10 = 21.
An infinite number of decimals. To prove this: 0.65, 0.625493, 0.6713485613495871346, etc...
No, but there is a way to prove that zero equals one.
Using faulty logic.
The diameter of a circle is its line of symmetry and the lines can be infinite
a0=(a-1\a-1)=a\a=1