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How many subnets and hosts per subnts can you get from 172.30.0.0?
The IP address 172.30.0.0 is a private IP address in the Class B range, which has a default subnet mask of 255.255.0.0 (or /16). If you use the default mask, you can create 65,536 addresses (2^16), allowing for 65,534 usable hosts per subnet (subtracting 2 for the network and broadcast addresses). If you further subnet this address, the number of subnets and hosts per subnet will depend on the subnet mask you choose. For example, using a /24 subnet mask would give you 256 subnets with 254 usable hosts in each.
How do you use 172.16.0.0 to create 6 subnets?
To create 6 subnets from the IP address 172.16.0.0, you need to determine how many bits to borrow from the host portion of the address. Since 2^3 = 8, borrowing 3 bits allows for 8 subnets, which is sufficient for your requirement of 6. This results in a subnet mask of 255.255.248.0 (or /21), providing each subnet with 2046 usable host addresses. The subnets would range from 172.16.0.0/21 to 172.16.7.0/21.
How many networks wil be created using 255.255.0.0 given a class A ip network?
Using a Class A IP network with a subnet mask of 255.255.0.0 (also known as /16), you can create 2^16 (or 65,536) subnets. This is because the first 16 bits are used for the network portion, leaving 16 bits for host addresses within each subnet. However, the number of usable networks may be slightly lower depending on reserved addresses.
What is a valid card number?
A valid credit card number is a card that is recognized as real and usable. An invalid card is either expired or falsified.
What is the total number of good usable copies from a single printing?
The total number of good usable copies from a single printing depends on various factors, including the quality of the printing process, the type of materials used, and the specific printing technology employed. Typically, a well-managed print run can yield a high percentage of usable copies, often around 90-95%, but this can vary. For a precise figure, one would need to consider the specific context of the printing job.
Given class C address with a default subnet mask How many possible subnets and usable hosts if 4 bits were borrowed?
that gives you 16 subnets with 14 usable IPs for hosts that is because one is for subnet and one for broadcas in that subnet for example: 192.168.1.0/28 - subnet number 192.168.1.15 -broadcast number usable IPs for hosts - IPs between them that is 14
How will you break a subnet into two smaller subnets?
To break a subnet into two smaller subnets, you need to extend the subnet mask to create additional bits for subnetting. For example, if you start with a /24 subnet (e.g., 192.168.1.0/24), you can change the mask to /25, which divides the original subnet into two subnets: 192.168.1.0/25 (with addresses from 192.168.1.0 to 192.168.1.127) and 192.168.1.128/25 (with addresses from 192.168.1.128 to 192.168.1.255). This effectively doubles the number of subnets while halving the number of usable IP addresses in each new subnet.
How many valid subnets do you get if you borrow 3 bits?
When you borrow 3 bits from the host portion of an IP address, you can create (2^3 = 8) valid subnets. However, one subnet is reserved for the network address and another for the broadcast address, leaving you with 6 usable subnets. Thus, by borrowing 3 bits, you obtain 6 valid subnets for use.
How many subnets and hosts per subnts can you get from 172.30.0.0?
The IP address 172.30.0.0 is a private IP address in the Class B range, which has a default subnet mask of 255.255.0.0 (or /16). If you use the default mask, you can create 65,536 addresses (2^16), allowing for 65,534 usable hosts per subnet (subtracting 2 for the network and broadcast addresses). If you further subnet this address, the number of subnets and hosts per subnet will depend on the subnet mask you choose. For example, using a /24 subnet mask would give you 256 subnets with 254 usable hosts in each.
How do you create 8 subnets for 192.168.1.024?
To create 8 subnets for the IP address 192.168.1.0, you need to use subnetting. Since 8 subnets require 3 additional bits (as 2^3 = 8), you can take 3 bits from the host part of the default subnet mask (255.255.255.0 or /24). This will change the subnet mask to 255.255.255.224 (/27), allowing for 8 subnets, each with 30 usable host addresses (2^5 - 2 = 30). The resulting subnets will range from 192.168.1.0 to 192.168.1.224.
How do you use 172.16.0.0 to create 6 subnets?
To create 6 subnets from the IP address 172.16.0.0, you need to determine how many bits to borrow from the host portion of the address. Since 2^3 = 8, borrowing 3 bits allows for 8 subnets, which is sufficient for your requirement of 6. This results in a subnet mask of 255.255.248.0 (or /21), providing each subnet with 2046 usable host addresses. The subnets would range from 172.16.0.0/21 to 172.16.7.0/21.
How many hosts in 512 subnets?
To determine the number of hosts in 512 subnets, we first need to understand the subnetting. If you have 512 subnets, that means you need 9 bits (since 2^9 = 512). Assuming you are using a standard classful subnet mask, the remaining bits from a total of 32 bits (IPv4) can be used for hosts. This would typically leave you with 23 bits for hosts, allowing for 2^23 - 2 = 8,388,606 usable hosts per subnet, after accounting for network and broadcast addresses.
How Do I Solve Custom Subnet Mask Problem 10?
.Hello everyone, Here's my overview: Hello everyone, I seem to have a problem with this custom subnet masking problem. Number needed usable hosts:60 Network Address:198.100.10.0 I've already figured these: Address Class:C Default Subnet Masks 255.255.255.0 Total Number Of Host Addresses:64 Number Of Usable Address:62. Cannot Figure Out: Total Number Of Subnets, Custom Subnet Masks (I got 255.255.255.240 but checked online and wasn't right). Can someone help me with this problem? Thanks.
How many bits are borrowed for the subnet?
Subnets are created in powers of 2 due to the way netmasks work. To accomodate 10 addresses, you would need a /28 (255.255.255.240) netmask, which would provide 14 usable IP addresses. Here are the details of that mask in a private network address area (192.168.x.x) Output from the unix "ipcalc" program: Address: 192.168.1.0 11000000.10101000.00000001.0000 0000 Netmask: 255.255.255.240 = 28 11111111.11111111.11111111.1111 0000 Wildcard: 0.0.0.15 00000000.00000000.00000000.0000 1111 => Network: 192.168.1.0/28 11000000.10101000.00000001.0000 0000 HostMin: 192.168.1.1 11000000.10101000.00000001.0000 0001 HostMax: 192.168.1.14 11000000.10101000.00000001.0000 1110 Broadcast: 192.168.1.15 11000000.10101000.00000001.0000 1111 Hosts/Net: 14 Class C, Private Internet With the /28 netmask, 192.168.1.0 is the network address, and unusable. 192.168.1.15 is the broadcast address, and is also non-assignable. This gives 14 usable addresses. A /29 netmask (one bit less) gives 6 usable addresses. To create 10 subnets, the size of the subnets would need to be known, and the process is similar, but the subnets would have different start and end addresses.
How you can calculate the total storage capacity of magnetic disk?
To calculate the total storage capacity of a magnetic disk, you need to multiply the number of tracks by the number of sectors per track and the number of bytes per sector. The formula is: Total Capacity = (Number of Tracks) × (Sectors per Track) × (Bytes per Sector). Ensure you consider the disk's format and any reserved space, as this may affect the usable capacity.
What number is a valid number?
A valid credit card number is a card that is recognized as real and usable. An invalid card is either expired or falsified.
What is the maximum number of usable hosts that can be treated if six hosts bits are available?
62
