There are a number of different ways. The one way which always works is using the quadratic formula.
So, the solutions of quadratic equation of the form ax2 + bx + c = 0 are
x = [-b ± sqrt(b2 - 4ac)]/(2a)
If b2 - 4ac, which is called the discriminant, is less than 0 then there is no real square root and so no real solution: if a > 0 the graph of the quadratic is either entirely above the x-axis and if a < 0 it is below. [The square roots do exist in the complex field but the fact that you asked this question indicates that you have not yet reached that level.]
There are other methods such as completing the square which is, in fact, the same as the above but you go through a lot more steps before getting to the same point!
Still another method is factorisation. This method is fine as long as you can easily work out two linear factors for the quadratic. A lot of high school quadratics that you will need to solve will be open to this approach but real life is not as simple!
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To find the roots (solutions) of a quadratic equation.
If the discriminant of the quadratic equation is equal or greater than zero it will have 2 solutions if it is less than zero then there are no solutions.
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
I suggest you use the quadratic formula.
There are an infinite number of different quadratic equations. The quadratic formula is a single formula that can be used to find the pair of solutions to every quadratic equation.