to find the average (a.k.a mean) of any set of numbers you add all of the numbers up, then divide by however many numbers there are. for ex: 2,7,5,9,4 1st step: 2+7+5+9+2= 25 2nd step: 25 divided by 5= 5 average equals=5
No, it is not. Example: the average of (5 and 7) is 6, and the average of (50, 60 and 70) is 60, but if we add all five numbers we have 192, so the overall average is 192 divided by 5 = 38.4 and the reason for that is we have more and bigger numbers in the second set.
The sum of the first five prime numbers is 28. The sum of the cubes of the first three prime numbers is 160. The average of 28 and 160 is 94.
8 10 12 14 16
The idea is to add the five numbers, then divide the result by 5 (in this case, you divide by 5, because there are 5 numbers).
That means that you multiply all five numbers.
I don't know what a pachymeter is. But here's how to get the average of any five numbers, no matter where they came from: -- Add up all five numbers. -- Divide the sum by 5 . The quotient is the average of the five numbers.
741,743,745,747,749
A flow chart is a diagram that represents the steps to finding a solution to a problem. To find the average of five numbers, all five must be added together, then the end number must be divided by 5. The flow chart will show these steps in boxes.
The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953
The average of five numbers whose sum is 200 will always be 40, no matter which numbers you choose. When finding an average, you add up the numbers (find the sum of the set), then divide by the number of terms. In this case, the sum will always be 200, and there will always be five terms. This will always result in an average of 40. Ex/ 1 + 2 + 3 + 4 + 190 = 200 200 / 5 = 40 40 + 40 + 80 + 24 + 16 = 200 200 / 5 = 40
7.4
it will be destroyed.
There is 100% chance.
If the five numbers need to be read from command-line, you'll have to parse the arguments (the function atoi() will come in handy there). If the five numbers are known at compile-time, you'll get a program like below: #include <stdio.h> int main(int argc, char **argv) { int a = 10; int b = 20; int c = 30; int d = 40; int e = 50; int result = (a + b + c + d + e) / 5; printf("The average of %d, %d, %d, %d and %d is %d\n", a, b, c, d, e, result); }
Just add all the numbers, then divide by the size of the set. For example, if you have a set of five numbers, add all of them, then divide the result by five.
Average of five numbers is 82 so their sum is 82*5 = 410. Average of four of them is 80, so their sum is 80*4 = 320. So the fifth number is 410 - 320 = 90.
No, it is not. Example: the average of (5 and 7) is 6, and the average of (50, 60 and 70) is 60, but if we add all five numbers we have 192, so the overall average is 192 divided by 5 = 38.4 and the reason for that is we have more and bigger numbers in the second set.