(9/3 + 6)*1 = 9
Without repeated digits, the answer is 7*6*5*4*3 = 2520
Using the digits 1, 3, and 5 exactly once, you can create different 3-digit numbers by permuting these digits. The number of permutations of 3 distinct digits is calculated as 3! (3 factorial), which equals 6. Therefore, the different numbers you can create are: 135, 153, 315, 351, 513, and 531. Thus, there are 6 different numbers that can be formed.
151200 numbers.
24
654321-100000= 554321 combinations
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
There are 3*2*1 = 6 of them.
123,456 would be the smallest number using all 6 digits. You arrange the numbers from lowest to highest.
Without using exponents, 9,631 is.
Without repeated digits, the answer is 7*6*5*4*3 = 2520
The answer is 6. (Here, the no. of digits = 1. Thus, Six times the no. of digits= 6 x 1 = 6)
151200 numbers.
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
24
2,401
654321-100000= 554321 combinations
18 can.