Here is the number line .
....-2, -7/4. -3/2 , -5/4, -1 , -3/4 , -1/2, -1/4, 0, 1/4, 1/2, 3/4, 1 , 5/4 , 3/2, 7/4, 2 ....
......................... ..------------------.. ..|.....|.....|.....|... ..0.....1...√4...3... ........................
The product of any non-zero number and its reciprocal is 1.
1 and (3/4) = 1.751.75 + 1.75 = 3.5 (or three and a half)
To represent the square root of 11.5 on a number line, we first need to approximate the value. The square root of 11.5 is approximately 3.39. On the number line, locate the whole number 3 and then estimate the position of 3.39 between 3 and 4. Mark this point on the number line to represent the square root of 11.5.
friends,root 10 is according to our pythagores thoream.root 10=square of 3 and square of 1 can be represented on a number line.
3 and a 1/4 is already a mixed number
51/4, or 12 and 3/4
3 And 0 Over 4
15/4 = 3 and 3/4
yes. -1.5,-3/4,-2/8,1
6
......................... ..------------------.. ..|.....|.....|.....|... ..0.....1...√4...3... ........................
1 (a whole).
3 of anything plus 3 more of the same thing is 6 of them.
The product of any non-zero number and its reciprocal is 1.
1 and (3/4) = 1.751.75 + 1.75 = 3.5 (or three and a half)
To represent the square root of 11.5 on a number line, we first need to approximate the value. The square root of 11.5 is approximately 3.39. On the number line, locate the whole number 3 and then estimate the position of 3.39 between 3 and 4. Mark this point on the number line to represent the square root of 11.5.