To represent -2 x 3 on a number line, first calculate the product, which is -6. Then, locate the point -6 on the number line, which is 6 units to the left of 0. You can mark this point clearly, indicating that -6 is the result of multiplying -2 by 3.
Since 132 is an even number (it ends in 2), it is divisible by 2 (a prime number).132 ÷ 2 = 66 (66 also is an even number, it ends in 6)66 ÷ 2 = 33 (33 is an odd number, it is not divisible by 2, but it is divisible by 3 which is a prime number, since the sum of its digits, 6, is divisible by 3)33 ÷ 3 = 11 (11 is a prime number).Now we have all the prime factors of 132, and we can represent 132 as a product of its prime factors such as,132 = 2 x 2 x 3 x 11 = 22 x 3 x 11
1, 2, 3 and 6 are the factors of their GCF, 6
A pronumeral is a letter that is used to represent a number (or numeral) in a problem.Neither 6 nor 18 has any of those. The common factors of 6 and 18 are 1, 2, 3 and 6.
Step 1 Find the prime factors of each number 36 = 2×2×3×3 = 2²×3² 72 = 2³×3² 108 = 2²×3³ Step 2 Find LCM L - Highest (Find the number with the highest exponent) C - Common (Find the common number EG. 2 and 3) M - Missing ( Take what ever is missing that is not common) LCM : 2³×3³ = 216 Your LCM is 216
Finding the Prime Factorization of 66To find the prime factorization of 66, find the lowest prime number that will divide evenly into 66. Since 66 is an even number, that number will be 2. Find the number which when multiplied by 2 equals 66. The number is 33. Write it down like this:2 X 33 = 662 is one of the prime factors of 66, but 33 is a composite number and must be factored. Find the lowest prime number that divides evenly into 33. The number cannot be 2 because 33 is an odd number. 3 is the lowest prime number that will divide evenly into 33. The number that when multiplied by 3 equals 33 is 11. Write it like this, keeping the 2 from the previous factorization:2 X 3 X 11All the factors are now prime numbers, so the prime factorization of 66 is:2 X 3 X 11This is one method that works for finding the prime factorization of any composite number.
To represent (\sqrt{8.47}) on a number line, first approximate the value. Since (2^2 = 4) and (3^2 = 9), we know (\sqrt{8.47}) is between 2 and 3. By calculating, we find (\sqrt{8.47} \approx 2.91). Mark this point slightly less than 3 on the number line for a visual representation.
Here is the number line . ....-2, -7/4. -3/2 , -5/4, -1 , -3/4 , -1/2, -1/4, 0, 1/4, 1/2, 3/4, 1 , 5/4 , 3/2, 7/4, 2 ....
From least to greatest: .....-4 -3 -2 -1 0 1 2 3 4..... etc
ne tala kaya banda kesi kottu
Remember: squareroot of 3 is smaller than 2 and bigger than 1. It is approx. 1.732
By root, I think you mean square root. The square root of 2 is approx. 1.414. The square root of 9 = 3, so this goes exactly at 3 on the number line. Square root 2 will be less than 1/2 way between 1 and 2 on the number line.
Oh, what a happy little question! To represent the square root of 3 on the number line, you simply find where it falls between whole numbers. Since the square root of 3 is between 1 and 2, you can place it around 1.7 on the number line with a little tick mark and a smile. Remember, there are no mistakes, just happy little accidents in math!
......................... ..------------------.. ..|.....|.....|.....|... ..0.....1...√4...3... ........................
-3...-2...-1...0...1...2...3To find the positive number when subtracting from a (-)number is finding the Absolute Value of the sum. Another way is changing the negative number to a positive and reversing the equation.*Such as, 1-(-3)--> +3-1. So than the answer is a positive 4.* Dots represent the actual line
It is: 0.5
To represent the square root of 11.5 on a number line, we first need to approximate the value. The square root of 11.5 is approximately 3.39. On the number line, locate the whole number 3 and then estimate the position of 3.39 between 3 and 4. Mark this point on the number line to represent the square root of 11.5.
friends,root 10 is according to our pythagores thoream.root 10=square of 3 and square of 1 can be represented on a number line.