In general, you need to know three consecutive parts of a triangle before
you can solve for any of the other three.
("Three consecutive parts" means two sides and the angle between them,
or two angles and the side between them.)
If you really only know two sides and nothing else, then you can't solve for
any of the unknown parts, because there are actually an infinite number of
different triangles that could have the same two sides that you're given.
If you were asked to find angle-A, as if it's possible, then there must be
something else that you know about the triangle besides side-a and side-b.
Is it by any chance a right triangle ? Or an isosceles triangle ? Or are you
given the sine, cosine, or tangent of anything ? Look around for one more
bit of information.
With ease, I suppose. The question depends on what you consider easy trigonometric functions.
Yes, this is a perfectly legitimate thing to do in the trigonometric functions. I will solve all your math problems. Check my profile for more info.
It depends on the relationship of the sides to the angle. Assuming that neither side a or side b are the hypotenuse (longest side of the right triangle) and that side A is opposite the angle A and side b is closest (adjacent) to angle A then side a over side b will give the tangent of the angle A. If either side a or side b is the hypotenuse then when multiplied together their relationship to the angle A will give either the Sine or the Cosine of the angle A. Tangent = Opposite side / Adjacent side. Sine = Opposite / Hypotenuse. Cosine = Adjacent / Hypotenuse. A full explanation with diagram is at the related link below:
The answer depends on what the question is and what other information you are given.
No, trigonometry can be used with any triangle, right angle or not. While the primary trigonometric functions are defined in relation to right triangles with hypoteneuse equal to 1, that is just a special case where the function is easier to define. Sine (theta), for instance, is opposite over hypotenuse, where the angle on the other end of adjacent is a right angle. Even if you don't have a right angle, the functions can help you find a superposition of a right triangle on any triangle, and that can help you solve many different kinds of problems. The laws of sines and cosines, for instance, apply to any triangle.
It depends on the details of the specific triangle.
With ease, I suppose. The question depends on what you consider easy trigonometric functions.
To solve trigonometry problems easily, make sure you have a good understanding of the basic trigonometric functions (sine, cosine, tangent) and their properties. Practice using trigonometric identities and formulas to simplify expressions. Visual aids such as diagrams can also help in understanding and solving trigonometry problems more easily.
Look there!
Yes, this is a perfectly legitimate thing to do in the trigonometric functions. I will solve all your math problems. Check my profile for more info.
To find the pronumeral in an angle, you first need to identify the angle in question. A pronumeral is a variable that represents an unknown value, typically denoted by a letter such as x, y, or z. Once you have identified the angle and the pronumeral representing it, you can use algebraic equations or geometric relationships to solve for the value of the pronumeral. This process often involves applying trigonometric functions or angle properties depending on the context of the problem.
The answer depends on the nature of the equations.
It depends on the relationship of the sides to the angle. Assuming that neither side a or side b are the hypotenuse (longest side of the right triangle) and that side A is opposite the angle A and side b is closest (adjacent) to angle A then side a over side b will give the tangent of the angle A. If either side a or side b is the hypotenuse then when multiplied together their relationship to the angle A will give either the Sine or the Cosine of the angle A. Tangent = Opposite side / Adjacent side. Sine = Opposite / Hypotenuse. Cosine = Adjacent / Hypotenuse. A full explanation with diagram is at the related link below:
The answer depends on what the question is and what other information you are given.
Use trigonometric identities to simplify the equation so that you have a simple trigonometric term on one side of the equation and a simple value of the other. Then use the appropriate inverse trigonometric or arc function.
if given the central angle and the area of the circle, then by proportion: Given angle / sector area = 360 / Entire area, then solve for the sector area
It isn't clear what you want to solve for. To solve trigonometric equations, it often helps to convert other angular functions (tangent, cotangent, secant, cosecant) into the equivalent of sines and cosines. However, the details of course depend on the specific case.