No. 642 is not evenly divisible by nine.
642 is composite. It is divisible by 2, 3, 107, 214, and 321.
1, 2, 3, 6, 107, 214, 321, 642
Just by looking at it, without trying any factors to see if they work, you can see-- 642 is even, i.e. divisible by 2, since it ends in '2'-- 642 is divisible by 3, since its digits add up to (6+4+2) = 12 which is divisible by 3.Just looking at 642, you already know of at least 2 factors that it has besides '1' and itself,so it can't be a prime number.
Yes, evenly
Yes and it is 107
5
here are some 2,3,4,6,8,12,13,16,24,26,32,48,52,321&642
Only by 6 evenly with no remainder
No, it is not evenly divisible by 3. The answer you get is 6,665.3333. A trick to tell is a number is divisible by 3 is to add up the digits and see if they are divisible by 3. In this case, 34 is not divisible by 3.
642 x 3 = 1926
693 is evenly divisible by 3. You can tell that at a glance because every one of its digits is evenly divisible by 3.