Only by 6 evenly with no remainder
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1, 2, 3, 6, 107, 214, 321, 642
To determine if a number is divisible by 6, we need to check if it is divisible by both 2 and 3. The number 34614 is divisible by 2 because it is even (the last digit is even). To check if it is divisible by 3, we sum the digits: 3 + 4 + 6 + 1 + 4 = 18, which is divisible by 3, so 34614 is divisible by 3. Therefore, 34614 is divisible by 6. To check if it is divisible by 9, we sum the digits again: 3 + 4 + 6 + 1 + 4 = 18, which is divisible by 9, so 34614 is divisible by 9 as well.
Yes.
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60, 107, 214, 321, 428, 535, 642, 1070, 1284, 1605, 2140, 3210, 6420
This statement is not always true. While it is true that if a number is divisible by 4, it is also divisible by 2, the reverse is not necessarily true. For example, the number 6 is divisible by 2 but not by 4. In general, being divisible by 2 is a necessary but not a sufficient condition for being divisible by 4.