If both matrices have the same number of columns and rows
ex:
{1 2 3 4} can not be added with {5 4} b/c they dont have the same amount of numbers
how to multiply two sparse matrices
Two matrices ( A ) and ( B ) are inverses of each other if their product results in the identity matrix. Specifically, this means that ( AB = I ) and ( BA = I ), where ( I ) is the identity matrix of the same size as ( A ) and ( B ). If both conditions are satisfied, then ( A ) and ( B ) are indeed inverses. If either product does not equal the identity matrix, then the matrices are not inverses.
No, it is not.
The matrix multiplication in c language : c program is used to multiply matrices with two dimensional array. This program multiplies two matrices which will be entered by the user.
Closed . . . .A+
Yes. In general, two matrices of the same size can be added.
how to multiply two sparse matrices
Two matrices ( A ) and ( B ) are inverses of each other if their product results in the identity matrix. Specifically, this means that ( AB = I ) and ( BA = I ), where ( I ) is the identity matrix of the same size as ( A ) and ( B ). If both conditions are satisfied, then ( A ) and ( B ) are indeed inverses. If either product does not equal the identity matrix, then the matrices are not inverses.
no
Let me correct you: two-dimensional arrays are used in programming to represent matrices. (Matrices are objects of mathematics, arrays are objects of programming.)
No, it is not.
[object Object]
The matrix multiplication in c language : c program is used to multiply matrices with two dimensional array. This program multiplies two matrices which will be entered by the user.
The two matrices and their answer must be of the same dimensions. Each element of the answer matrix is the sum of the elements in the corresponding elements on the matrices that are being added. In algebraic form, if A = {aij} where 1 ≤ i ≤ m, 1 ≤ j ≤ n is an mxn matrix B = {bij} where 1 ≤ i ≤ m, 1 ≤ j ≤ n is an mxn matrix and C = {cij} = A + B, then C is an mxn matrix and cij = aij + bij for all 1 ≤ i ≤ m, 1 ≤ j ≤ n
use mantel test
Closed . . . .A+
a,b,c,d,