To get 24 using 1 3 4 and 6 once you do 6 times 4
Assuming that you can only use each number once and that you can use any function the solution is the following:Step 19-1 & 2+1(This uses all 4 numbers and leaves you with 8 & 3)Step 28*3 = 24
9 - 8 =1 4 -1 =3 3*8= 24
7-3= 4-1= 3x8= 24
If a*3=24: a*3/3 = 24/3 a = 8 If a**3=24 (a**3)**(1/3) = 24**(1/3) a = 24**(1/3)
To get 24 using 1 3 4 and 6 once you do 6 times 4
the real question is : Use each of the numbers 1, 3, 4, 6 exactly once with any of the four basic math operations (addition, subtraction,multiplication,division) to total 24.each number must be used once and only once. 24= 3/4 = 0,75 1 - 0,75 = 0,25 6/ 0,25 = 24.
It is simply: 1*2*3*4 = 24
Assuming that you can only use each number once and that you can use any function the solution is the following:Step 19-1 & 2+1(This uses all 4 numbers and leaves you with 8 & 3)Step 28*3 = 24
6/3 x (7+5)=24 or 3*(7+6-5) = 24
4! * 2 - 1 - 3 =24*2 - 1 - 3 = 48 - 1 - 3 = 44
Assuming you have to use ALL the numbers.... 6 - 5 = 1 then 3 x 8 = 24. 24 x 1 = 24.
9 - 8 =1 4 -1 =3 3*8= 24
7-3= 4-1= 3x8= 24
If a*3=24: a*3/3 = 24/3 a = 8 If a**3=24 (a**3)**(1/3) = 24**(1/3) a = 24**(1/3)
6(7 - (2 + 1)) = 24 2 plus 1 equals 3. 7 minus 3 equals 4. 4 times 6 equals 24.
4*3*2*1 = 24