A percent is simply a proportion out of 100.
use the rule: is / of = percent / 100reword the question in your head What is 16 percent of 90?(percent = 16) (of = 90) is is the unknown pick a variable -- xx / 90 = 16 / 100 now solve for xx = 14.4
There is no "should" or "should not". The depends on the question that you are trying to answer.
You can use the equivalent form of the percent proportion, which is expressed as ( \text{part} = \text{percent} \times \text{whole} ), to solve percent problems by identifying the part (the amount you want to find), the percent (the percentage given), and the whole (the total amount). By rearranging the formula, you can solve for the unknown variable. For example, if you need to find 20% of 50, you can calculate it as ( \text{part} = 0.20 \times 50 ), leading to the solution of 10.
A simple tool to remember is: IS over OF equals percent over 100.If we put this into a proportion, we get:IS/OF = percent/100.Just put all percent problems into this format, and solve the proportion.Example: 12.5 IS what percent OF 75?Or,12.5 IS | what percent | OF 75?Just put these numbers into the proportion: (We will use x for the percent, as that is the unknown we are solving for)12.5/75 = x/100.Then solve by cross multiplying:75x = 1250.Then divide by 75:x = 1250/75,x = 16 2/3 %
To find a percent.
100
use the rule: is / of = percent / 100reword the question in your head What is 16 percent of 90?(percent = 16) (of = 90) is is the unknown pick a variable -- xx / 90 = 16 / 100 now solve for xx = 14.4
There is no "should" or "should not". The depends on the question that you are trying to answer.
You can use the equivalent form of the percent proportion, which is expressed as ( \text{part} = \text{percent} \times \text{whole} ), to solve percent problems by identifying the part (the amount you want to find), the percent (the percentage given), and the whole (the total amount). By rearranging the formula, you can solve for the unknown variable. For example, if you need to find 20% of 50, you can calculate it as ( \text{part} = 0.20 \times 50 ), leading to the solution of 10.
A simple tool to remember is: IS over OF equals percent over 100.If we put this into a proportion, we get:IS/OF = percent/100.Just put all percent problems into this format, and solve the proportion.Example: 12.5 IS what percent OF 75?Or,12.5 IS | what percent | OF 75?Just put these numbers into the proportion: (We will use x for the percent, as that is the unknown we are solving for)12.5/75 = x/100.Then solve by cross multiplying:75x = 1250.Then divide by 75:x = 1250/75,x = 16 2/3 %
Because you simply set it up in a proportion box, for example if you have the fraction 4/8 you put the 4 on top of the 8 and 100 next to the 8 because with percents you always use 100. then solve,
To find a percent.
To solve ratio, proportion, and percent problems, first convert the problem into a fraction if necessary. For percentages, express the percent as a decimal (e.g., 25% as 0.25) and then apply it to the relevant quantity. Use cross-multiplication for proportions to find unknown values, and remember that the formula for percent is: Percent = (Part/Whole) × 100. Finally, ensure to simplify your answers where possible for clarity.
The percent proportion can be used to solve real-world problems by setting up a ratio that compares a part to the whole, expressed as a percentage. For example, if you want to find out what percentage of a class passed an exam, you can set up the equation ( \frac{\text{part}}{\text{whole}} = \frac{\text{percent}}{100} ). This allows you to easily calculate unknown values, such as the percentage of sales tax on an item or the proportion of a budget allocated to different expenses. By applying this formula, you can make informed decisions based on quantitative data.
To solve a proportion, you can use the cross-multiplication method. If you have a proportion in the form ( \frac{a}{b} = \frac{c}{d} ), you can set up the equation ( a \times d = b \times c ). This allows you to find the unknown variable in the proportion by rearranging the equation as needed.
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