Q: How can you use slope ratio to find a side to a triangle?

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Divide the length of a side of one triangle by the length of the corresponding side of the other triangle.

The ratio of the length of the side in the big triangle to the length of the corresponding side in the little triangle is the scale factor.

11 1/2 to 4 1/4

Not too sure about the question as there is no triangle pictured at the right. But in general the area of a triangle is 0.5*base*perpendicular height

Its area is 0.5*36*48 = 864 square cm and it is a right angle triangle

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In a triangle there are three angle.So, the side opposite to the greatest angle will be greatest side in the triangle and hence it will be the slope of the triangle. you can find slope of any side of the triangle by finding tangent of the angle made by it to the horizontal side eg. place one side of the triangle horizontally. to find the slope of any side A, drop a normal from the apex to intersect the imaginary horizontal line.measure the length(l1) of the normal. measure the distance (l2) between the intersecting point and other end of side A. l1/l2 will give you the slope of side A.

Divide the length of a side of one triangle by the length of the corresponding side of the other triangle.

For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)

You divide the length of the shortest side by the length of the longest side.

The ratio of the length of the side in the big triangle to the length of the corresponding side in the little triangle is the scale factor.

The tangent ratio.

it also depends on what grade you are in so it depends on what you are doing it with for example if you had a graph it would be for slope if it is for a triangle it would be the missing side

They are in the same proportion as the sines of the angles that are opposite them.

11 1/2 to 4 1/4

is called the cosine ratio

Not too sure about the question as there is no triangle pictured at the right. But in general the area of a triangle is 0.5*base*perpendicular height

In a right triangle, two of the angles are acute ones. Referring to one of the acute angles, the ratio of the side opposite it to the side adjacent to it is the tangent of the angle.