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What is the value of cos -90?
cos90=0
What is the value of cosx at -90?
at -90 degrees the value of cos(x) is 0.
Can two non-zero vector got a zero resultant?
Yes.If the angle between them is 90 degrees. As we know that A.B=|A| |B| cos (phi). When phi=90 degree,cos 90=0. Hence A.B= |A| |B| *0 =0.
Why tan A 90 degree is not solve?
I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.
If y equals arc cos 0 then y is equal to 0 1 90 or 180?
arccos(0) = 90 + 360.n (n is an element of the integers) and 90 and 360 are in degrees. Therefore if the answer is in the subset 0<x<360 or something similar, Then the answer is 90.
What is the value of cos -90?
cos90=0
What is the value of cosx at -90?
at -90 degrees the value of cos(x) is 0.
Why is sine 30 the same as cosine of 60?
sin(30) = sin(90 - 60) = sin(90)*cos(60) - cos(90)*sin(60) = 1*cos(60) - 0*sin(60) = cos(60).
What are the 6 trig functions for 0 degrees 90 degrees 180 degrees 270 degrees?
sin(0) = 0, sin(90) = 1, sin(180) = 0, sin (270) = -1 cos(0) = 1, cos(90) = 0, cos(180) = -1, cos (270) = 0 tan(0) = 0, tan (180) = 0. cosec(90) = 1, cosec(270) = -1 sec(0) = 1, sec(180) = -1 cot(90)= 0, cot(270) = 0 The rest of them: tan(90), tan (270) cosec(0), cosec(180) sec(90), sec(270) cot(0), cot(180) are not defined since they entail division by zero.
Can two non-zero vector got a zero resultant?
Yes.If the angle between them is 90 degrees. As we know that A.B=|A| |B| cos (phi). When phi=90 degree,cos 90=0. Hence A.B= |A| |B| *0 =0.
What is tan of 90 degrees?
On the unit circle at 90 degrees the 90 degrees in radians is pi/2 and the coordinates for this are: (0,1). The tan function = sin/cos. In the coordinate system x is cos and y is sin. Therefore (0,1) ; cos=0, & sin=1 . Tan=sin/cos so tan of 90 degrees = 1/0. The answer of tan(90) = undefined. There can not be a 0 in the denominator, because you can't devide by something with no quantity. Something with no quantity is 0. Or, on a limits point of view, it would be infinity.
Why tan A 90 degree is not solve?
I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.
If y equals arc cos 0 then y is equal to 0 1 90 or 180?
arccos(0) = 90 + 360.n (n is an element of the integers) and 90 and 360 are in degrees. Therefore if the answer is in the subset 0<x<360 or something similar, Then the answer is 90.
Why is the tangent of 90 degrees undefined?
tan(x) = sin(x) /cos(x).When x = 90 degrees then cos(x) = 0 so tan(x) requires division by zero - which is not defined.
Determine the measure of angle A if 0 degrees is smaller than or equal to A which is smaller than or equal to 90 degrees and cos125 degrees equals negative cos A?
cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
What is the value of tan -90?
Assuming you mean -90 degrees, not radians: tan (-90) = [sin(-90)]/[cos(-90)] = (-1) / 0 You cannot divide by zero. tan (-90) is undefined/does not exist.
What is the value of power factor for a pure inductor?
Angle between v and i is 90 deg so, cos 90 = 0 Same for pure capacitor
