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Kathy wanted to arrange some cards in pairs but was card short She tried to arrange by fives and was still one card short She finally arranged the cards by sevens What is the least number of cards?
Your question doesn't really make much sense.. but if you mean't "Kathy wanted to arrange some cards in pairs but was one card short. She tried to arrange by fives and was still one card short. She finally arranged the cards by sevens. What is the least number of cards you can have?" This is the answer. List the multiples of 7. 7, 14, 21, 28, 35, 42, 49... The answer has to be odd because she tried to arrange in PAIRS but was ONE short. (It is always 1 higher then a multiple of two so that makes it odd). Knock off all even numbers. Remaining list of multiples of 7. 7, 21, 35, 49... The answer has to end with 4 or 9 because she tried to arrange the cards in fives but was one short. eg. 4, 9, 14, 19, 24, 29, 34, 39...(it is always 1 lower then a multiple of five). Knock of numbers that don't end with 4 or 9. Remaining list of multiples of 7. 49. The answer is 49. It is the least number of cards she could possibly have. I hope I didn't answer too late. :D Good Luck. - gigaturtle
How many different ways can you arrange 4 baseball cards into an album side by side?
4*3*2*1 = 24 ways.
Take ten cards numbered 0 to 9 each time use all ten cards arrange the cards to make five numbers that are multiple of 5?
To create five numbers that are multiples of 5 using the ten cards numbered 0 to 9, you can arrange them as follows: Use the cards 0, 5, 6, 7, and 8 to form the number 5,687 (multiple of 5). Use the cards 0, 1, 2, 5, and 9 to form the number 9,521 (multiple of 5). Use the cards 0, 3, 4, 5, and 8 to form the number 8,543 (multiple of 5). Use the cards 0, 2, 5, 6, and 7 to form the number 7,652 (multiple of 5). Use the cards 0, 1, 4, 5, and 9 to form the number 9,541 (multiple of 5).
What are the rules for Blackjack?
The basic rules are, you get two cards and the dealer gets two cards. Whichever hand is closer to 21 without going over, wins. After you get your first two cards, you can take additional cards if you choose, until you decide to stop, or until you "bust" which means you go over 21.
How many numbers of ways you can arrange 32 different cards between 4 players without repetition?
I'm pretty sure the answer is 32!/(8!)4 which is 99 561 092 450 391 000.
