To create five numbers that are multiples of 5 using the ten cards numbered 0 to 9, you can arrange them as follows:
The answer depends on the numbers on the cards in the bag!
Your question doesn't really make much sense.. but if you mean't "Kathy wanted to arrange some cards in pairs but was one card short. She tried to arrange by fives and was still one card short. She finally arranged the cards by sevens. What is the least number of cards you can have?" This is the answer. List the multiples of 7. 7, 14, 21, 28, 35, 42, 49... The answer has to be odd because she tried to arrange in PAIRS but was ONE short. (It is always 1 higher then a multiple of two so that makes it odd). Knock off all even numbers. Remaining list of multiples of 7. 7, 21, 35, 49... The answer has to end with 4 or 9 because she tried to arrange the cards in fives but was one short. eg. 4, 9, 14, 19, 24, 29, 34, 39...(it is always 1 lower then a multiple of five). Knock of numbers that don't end with 4 or 9. Remaining list of multiples of 7. 49. The answer is 49. It is the least number of cards she could possibly have. I hope I didn't answer too late. :D Good Luck. - gigaturtle
The numbers on the cards are numbered 2 through 10. Ace, Jack, Queen, and King do not have numbers. So add up 2 through 10 and get 54. There are 4 suits so 4 * 54 = 216.
The first step is to determine what the experiment is: rolling a pair of dice, drawing two cards from a deck of playing cards, selecting numbered cards?
There are twenty even-numbered card in a standard deck of 52 playing cards, the 2, 4, 6, 8, and 10 of Spades, Diamonds, Clubs, and Hearts.
it is impossible
The answer depends on the numbers on the cards in the bag!
36 cards, numbered 2-10, x 4 suits.
Your question doesn't really make much sense.. but if you mean't "Kathy wanted to arrange some cards in pairs but was one card short. She tried to arrange by fives and was still one card short. She finally arranged the cards by sevens. What is the least number of cards you can have?" This is the answer. List the multiples of 7. 7, 14, 21, 28, 35, 42, 49... The answer has to be odd because she tried to arrange in PAIRS but was ONE short. (It is always 1 higher then a multiple of two so that makes it odd). Knock off all even numbers. Remaining list of multiples of 7. 7, 21, 35, 49... The answer has to end with 4 or 9 because she tried to arrange the cards in fives but was one short. eg. 4, 9, 14, 19, 24, 29, 34, 39...(it is always 1 lower then a multiple of five). Knock of numbers that don't end with 4 or 9. Remaining list of multiples of 7. 49. The answer is 49. It is the least number of cards she could possibly have. I hope I didn't answer too late. :D Good Luck. - gigaturtle
7, 42, 63, 98, 105
The numbers on the cards are numbered 2 through 10. Ace, Jack, Queen, and King do not have numbers. So add up 2 through 10 and get 54. There are 4 suits so 4 * 54 = 216.
The first step is to determine what the experiment is: rolling a pair of dice, drawing two cards from a deck of playing cards, selecting numbered cards?
This can be done in many ways: e.g. 0,6,2,7,1,5,8,4,9,3
If you are referring to card numbers, no. Pokemon cards have been produced for at least the past twenty years. There are 649 Pokemon, each has multiple cards.
Yes, they are.
There are twenty even-numbered card in a standard deck of 52 playing cards, the 2, 4, 6, 8, and 10 of Spades, Diamonds, Clubs, and Hearts.
The numbered cards are 2-10, so it's (2+3+4+5+6+7+8+9+10) * 4 which is 216.