The deriviative of f(x) = x is 1 because the slope of the function f(x) = x is 1.
Recall the slope-intercept form of a line. The equation f(x) = x can also be stated as y = mx+b, where m is 1 and b is 0. The slope is m, or 1, and the deriviative of f(x) is the slope of f(x), which is m or 1, in this case.
The differentiation of sin x plus cosx is cos (x)-sin(x).
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
f(x)=x/4 + 4/x f'(x) = 1/4 - 4/x^2
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
( u(x+h) - u(x) )/ h
It equals y+1
The differentiation of sin x plus cosx is cos (x)-sin(x).
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
differentiation of sin x + cos x.
f(x)=x/4 + 4/x f'(x) = 1/4 - 4/x^2
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
The derivative is 1/(1 + cosx)
( u(x+h) - u(x) )/ h
There is no single formula for differentiation and anti-differentiation.The deriviative of a function y = f(x) is the limit of delta y over delta x as delta x approaches zero.OR:If f(x)=axn,f'(x)=(an)xn-1The deriviative of 2x3 would be 6x2.The anti-deriviative of a function is the reverse operation, i.e. the function is the deriviative of the anti-deriviative.Anti differentiation introduction:Anti differentiation is also called as integration process. It gives the reverse value of the differentiation equation. Anti differentiation is also called as anti derivative of the function. In this anti differentiation, f(x) is anti derivative of the function F(x). Anti differentiation is used for finding the area of the region under the certain curve. Anti differentiation symbol is denoted as ∫.General formula for anti differentiation:∫ xn dx = [xn + 1 / (n + 1)]+ c∫ k dx = k ∫ dx∫ udv = uv - ∫ v du∫ (w + y) dx = ∫ w dx + ∫ y dxanti-differentiation
y = sin(x+y) cos( x + y )[(1 + y')] = y' cos(x + y ) + y'cos(x + y ) = y' y'-y'cos( x+ y) = cos( x + y ) y'[1-cos(x+y)]= cos(x+y) y'= [cos(x+y)]/ [1-cos(x+y)]
solution: y = 0 x = -1
The value of x that satisfies -9 multiplied by x equals 1 is x = -1/9.